How does one ignore a void value?

hey there everybody,
i've been working parallax rfid reader/writer got   it's super awesome, , can read data fine, want try write it. decided write function (hooray me!) can't work - error keep getting follows:

rfid.cpp: in function 'void do_rfid_write(char*)':
rfid:125: error: void value not ignored ought be
rfid:128: error: void value not ignored ought be

here's code write function, , can include rest of code if anyone's interested. how can test see if void, , ignore if so?

quote

void do_rfid_write(char indata[]){
  for(int = 0; < sizeof(indata)/sizeof(char) && < maxaddress*4; i++){
    sendwritecommand(i/4); // because can store 4 chars (or bytes) per address

    while(!myserial.available()){
    }

    statuscode = myserial.print(indata); // <- line 125, fails first
    while(statuscode != err_ok){
      sendwritecommand(i);
      statuscode = myserial.print(indata); // <- fails second
    }

    serial.print("wrote address ");
    serial.println(i);
  }
  serial.println("finished write");
}

code: [select]

statuscode = myserial.print(indata[i]);
myserial.print() not return value. can't assign return code function not return value variable.

code: [select]

   while(statuscode != err_ok){
     sendwritecommand(i);
     statuscode = myserial.print(indata[i]); // <- fails second
   }
this makes no sense. since myserial.print() not return value, value (doesn't) return can not possibly err_ok. or, else matter.

to answer original question, 1 "ignores" nothing not trying save it.

Arduino Forum > Forum 2005-2010 (read only) > Software > Syntax & Programs > How does one ignore a void value?

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