Wrestling with 2 switches and timing

hi all, first project , in trouble.

i want build right left signaller car. mean indicators.
i have 2 switches on steering wheel. left , right. (i don't have space in car normal stalk on steering column.)

if press left, want system check if left on, , switch off. if off, switch on. if pressed briefly, third of second, want on 2 seconds , go off automatically.

if press right , left on, want left go off , right go on.


i tried modified debounce, ran trouble , found swpressed routine, tried that. did not work because have 2 switches can pressed.

so think using following pseudo code:

code: [select]



set pins

start loop

check state of switch1
  if low, , time1 empty, set time1
     else
    set timediff1 now-time1  
//so loop until switch1 becomes high

if switch1 high , timediff1 != 0 then
     if timediff1> debounce, then
        if timediff1 > longlimit, then
          check light2
            if on, switch off
          check light1
            if on, switch off, else switch on
        else
           switch on 2 seconds
           // thought of simple delay() mess timer
end of ifs
timediff1=0
time1=0        


same checks switch2
         
end of loop



that's thinking of doing.
or there easier way?

i thinking of doing actual checks of timediff in separate function, pull out of loop. idea?

i thought easy, used event driven software.
so harder thought. there 2 switches.

i have read stuff on interfacing relays , so, think got sussed. realtime stuff, whew.

i love comments on try. sure going messy, come with.

thanks in advance

lykle

quote

i thought easy, used event driven software.

if you're comfortable in event-driven terms, why not make event system?  store last known state of system, , fire event when state changes.

code: [select]

#define n 2
byte pins[n] = { 9, 10 };
byte switches[n] = { low, low };
long when[n] = { 0, 0 };

void loop()
{
   long = millis();
   for (int = 0; < n; i++)
   {
       byte pushed = digitalread(pins[i]);
       if (switches[i] != pushed)
       {
           if (pushed)
               onbuttonpressed(i);
           else
               onbuttonreleased(i, when[i] - now);
           when[i] = now;
           switches[i] = pushed;
       }
   }    
}

void onbuttonpressed(byte button)
{
   // if button's pushed
}

void onbuttonreleased(byte button, long held)
{
   // if button's released
   // learn how long held
}

i'm not saying complete, or if it's best way go, can adapt whole system work in way want work.

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