combine two 8 bit integers into a 16 bit integer

i have 2 8 bit integers want combine 1 unsigned 16 bit integer.

actually first byte (8 bits) high order bits, second byte low order bits.  i reading these eeprom.  so read these 2 bytes eeprom, , want combine them 1 16 bit unsigned integer.

what "correct" way combine these two?  i guessing there easy way first shift in high order bits, shift in low order bits?

thanks
chad

there few ways can this:

1) unsigned int word = high_byte * 256 + low_byte;

2) unsigned int word = ((unsigned int)high_byte << + low_byte

you can pointers, gets little more complicated.


- ben

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