'blushing' LEDs

howdy! i'm making simple circuit 2 force sensors , 2 leds. need happen have leds both light when 1 or both of force sensors has pressure applied it.

here original code using 1 force sensor , 1 led:

quote

/*

"one never dangerous when 1 has no shame, when 1 has grown old blush."
-marquis de sade (brainyquote.com)

*/

int ledvalue = 0; // led brightness
int ledpin1 = 9;       // led connected digital pin 9
int sensorpin = 0;       // force sensor connected analog pin 0
int sensorvalue = 0;       // variable store value coming sensor

void setup()
{       
 pinmode(ledpin1, output);       // sets ledpin1 output
 serial.begin(9600);       //initialize serial port
 digitalwrite(ledpin1, high);       // turn led on
}       

void loop()       // run on , on again
{
 sensorvalue = analogread(sensorpin);
 ledvalue = map(sensorvalue,0,1000,0,255); // set high , low outputs of sensor , led
 analogwrite(ledpin1, ledvalue); // turn led on @ brightness set sensor
 serial.println(sensorvalue);       // send value computer
 delay(100);       // delay 1/10 of second

 if (sensorvalue>300){ // if value coming computer greater 300
   analogwrite(ledpin1, high); // turns on led
 }

 else {
   (sensorvalue<300);
   { // if value coming computer less 300
     analogwrite(ledpin1, low); // turns off leds
   }
 }
}      

the second led attached pin 5 , second force sensor attached analog pin 1. can post attempts @ adding second force sensor , led if need however, @ point, code more little muddled.

any suggestions welcome!

the code add before setup() pretty straightforward. did have problems that?

the code add in setup() pretty straightforward. did have problems that?

in loop, need read both force sensors. that's easy.

code: [select]

  analogwrite(ledpin1, high); // turns on led
actually, code turn way off, if led connected pwm pin, since high has value of 1. if led not connected pwm pin, code nothing.

code: [select]

  (sensorvalue<300);
what think code doing?

post code came with, , we'll working. you'll learn more if give answer.

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